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Solution K3-68 (Figure K3.6 condition 8 SM Targ 1989)

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Uploaded: 26.03.2018
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Solution K3-68 (Figure K3.6 condition 8 SM Targ 1989) Solution K3-68 (Figure K3.6 condition 8 SM Targ 1989)


Solution K3-68 (Figure K3.6 condition 8 SM Targ 1989)

The planar mechanism consists of rods 1, 2, 3, 4 and the slider B or E (Fig. K.0 - K3.7) or from the rods 1, 2, 3 and the sliders B and E (Fig. K3.8, K3. 9) connected to each other and to fixed supports O1, O2 by hinges; Point D is in the middle of the rod AB. The lengths of the rods are l1 = 0.4 m, l2 = 1.2 m, l3 = 1.4 m, l4 = 0.6 m, respectively. The position of the mechanism is determined by the angles α, β, γ, φ, θ. The values ​​of these angles and other specified values ​​are given in Table. KZa (for Figure 0-4) or in Table. KZB (for Figure 5-9); while in Table. КЗа ω1 and ω4 are constant quantities. Determine the values ​​indicated in the tables in the columns "Find". Arc arrows in the figures show how the corresponding angles should be plotted during the construction of the mechanism drawing: in the direction of or against the clockwise direction (for example, the angle γ in Figure 8 should be deposited from DB along the clockwise direction, and in Figure 9 - arrows, etc.). Draw a drawing from the rod, the direction of which is determined by the angle α; the slider with guides for greater visibility is represented as in the example of short-circuit (see Fig. The given angular velocity and angular acceleration are assumed to be directed counterclockwise, and the given velocity vB and the acceleration aB are from point B to b (in Fig. 5-9).

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